Question:
The reaction of $\mathrm{H}_{3} \mathrm{~N}_{3} \mathrm{~B}_{3} \mathrm{Cl}_{3}$ (A) with $\mathrm{LiBH}_{4}$ in tetrahydrofuran gives inorganic benzene $(B)$. Further, the reaction of (A) with (C) leads to $\mathrm{H}_{3} \mathrm{~N}_{3} \mathrm{~B}_{3}(\mathrm{Me})_{3}$. Compounds (B) and (C) respectively, are:
Correct Option: , 2
Solution:
