Question:
Mark $(\sqrt{ })$ against the correct answer in the following:
$f y=x^{\sqrt{x}}$ then $\frac{d y}{d x}=?$
A. $\sqrt{x} \cdot x^{(\sqrt{x}-1)}$
B. $\frac{x^{\sqrt{x}} \log x}{2 \sqrt{x}}$
C. $\mathrm{x}^{\sqrt{\mathrm{x}}}\left\{\frac{2+\log \mathrm{x}}{2 \sqrt{\mathrm{x}}}\right\}$
D. none of these
Solution:
