Question:
$T_{0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to
$\frac{1}{16}$ times of its initial value, the modified time period is:
Correct Option: , 4
Solution:
$\mathrm{T}_{0}=2 \pi \sqrt{\frac{\ell}{\mathrm{g}}}$
New time period $\mathrm{T}=2 \pi \sqrt{\frac{\ell / 16}{\mathrm{~g}}}=\frac{2 \pi}{4} \sqrt{\frac{\ell}{\mathrm{g}}}$
$\mathrm{T}=\frac{\mathrm{T}_{0}}{4}$
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