Question:
Mark $(\sqrt{)}$ against the correct answer in the following:
If $\mathrm{y}=\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+\sqrt{\mathrm{x}+}}} \ldots \infty$ then $\frac{\mathrm{dy}}{\mathrm{dx}}=$ ?
A. $\frac{1}{(2 y-1)}$
B. $\frac{1}{\left(y^{2}-1\right)}$
C. $\frac{2 y}{\left(y^{2}-1\right)}$
D. none of these
Solution: