Solve this following

Question:

If $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{Ag}_{2} \mathrm{CO}_{3}$ is $8 \times 10^{-12}$, the molar solubility of $\mathrm{Ag}_{2} \mathrm{CO}_{3}$ in $0.1 \mathrm{M} \mathrm{AgNO} 3$ is :

  1. $8 \times 10^{-12} \mathrm{M}$

  2. $8 \times 10^{-10} \mathrm{M}$

  3. $8 \times 10^{-11} \mathrm{M}$

  4. $8 \times 10^{-13} \mathrm{M}$


Correct Option: , 2

Solution:

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