Let $z \in C$ be such that $|z|<1$. If $\omega=\frac{5+3 z}{5(1-z)}$, then:-
$5 \operatorname{Im}(\omega)<1$
$4 \operatorname{Im}(\omega)>5$
$5 \operatorname{Re}(\omega)>1$
$5 \operatorname{Re}(\omega)>4$
Correct Option: , 3
Leave a comment
All Study Material
