Question:
Mark $(\sqrt{)}$ against the correct answer in the following:
If $y=\sqrt{x \sin x}$ then $\frac{d y}{d x}=?$
A. $\frac{(x \cos x+\sin x)}{2 \sqrt{x \sin x}}$
B. $\frac{1}{2}(x \cos x+\sin x) \cdot \sqrt{x \sin x}$
C. $\frac{1}{2 \sqrt{x \sin x}}$
D. none of these
Solution:
