Question:
Mark $(\sqrt{)}$ against the correct answer in the following:
If $y=\sqrt{\frac{1+\sin x}{1-\sin x}}$ then $\frac{d y}{d x}=?$
A. $\frac{1}{2} \sec ^{2}\left(\frac{\pi}{4}-\frac{\pi}{2}\right)$
B. $\frac{1}{2} \operatorname{cosec}^{2}\left(\frac{\pi}{4}-\frac{\pi}{2}\right)$
C. $\frac{1}{2} \operatorname{cosec}^{2}\left(\frac{\pi}{4}-\frac{\pi}{2}\right) \cot \left(\frac{\pi}{4}-\frac{\pi}{2}\right)$
D. none of these
Solution:
