Question: $\operatorname{Ge}(Z=32)$ in its ground state electronic configuration has x completely filled orbitals with $\mathrm{m}_{l}=0 .$ The value of $\mathrm{x}$ is
Solution:
Completely filled orbital with $\mathrm{m}_{t}=0$ are
$=1+1+1+1+1+1+1$
$=7$
So Answer is 7
