$\left(\sec ^{2} 60^{\circ}-1\right)=?$
(a) 0(b) 2(c) 3(d) 4
As we know that,
$\sec 60^{\circ}=2$
By substituting the value, we get
$\left(\sec ^{2} 60^{\circ}-1\right)=(2)^{2}-1$
$=4-1$
$=3$
Hence, the correct option is (c).
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