Question:
Let $(x+10)^{50}+(x-10)^{50}=a_{0}+a_{1} x+a_{2} x^{2}+\ldots \ldots$
$+\mathrm{a}_{50} \mathrm{x}^{50}$, for all $\mathrm{x} \in \mathrm{R}$, then $\frac{\mathrm{a}_{2}}{\mathrm{a}_{0}}$ is equal to:-
Correct Option: , 4
Solution:
$(10+x)^{50}+(10-x)^{50}$
$\Rightarrow a_{2}=2 .{ }^{50} C_{2} 10^{48}, a_{0}=2.10^{50}$
$\frac{\mathrm{a}_{2}}{\mathrm{a}_{0}}=\frac{{ }^{50} \mathrm{C}_{2}}{10^{2}}=12.25$
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