Solve this

Given: $5 x+7 y=-2$

$4 x+6 y=-3$

Using Cramer's Rule, we get

$D=\mid 5 \quad 7$

$4 \quad 6 \mid=30-28=2$

$D_{1}=\mid \begin{array}{ll}-2 & 7\end{array}$

$-3 \quad 6 \mid=-12+21=9$

$D_{2}=\mid 5-2$

$4-3 \mid=-15+8=-7$

Now,

$x=\frac{D_{1}}{D}=\frac{9}{2}$

$y=\frac{D_{2}}{D}=\frac{-7}{2}$

$\therefore x=\frac{9}{2}$ and $y=\frac{-7}{2}$