If $p(x)=x=4$, then $p(x)+p(-x)=?$
(a) 0
(b) 4
(c) $2 x$
(d) 8
Let:
$p(x)=(x+4)$
$\therefore p(-x)=(-x)+4$
$=-x+4$
Thus, we have
$p(x)+p(-x)=\{(x+4)+(-x+4)\}$
= 4 + 4
=8
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