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Question:

If A(2, -5), B(-2, 5), C(x, 3) and D(1, 1) be four points such that AB and CD are perpendicular to each other, find the value of x.

 

Solution:

For two lines to be perpendicular, their product of slope must be equal to -1.

Given points are A(2, -5),B(-2, 5) and C(x, 3),D(1, 1)

slope $=\left(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\right)$

$\Rightarrow$ Slope of line $A B$ is equal to

$\left(\frac{5+5}{-2-2}\right)$

$=\left(\frac{10}{-4}\right)$

$=\left(\frac{-5}{2}\right)$

$=-2.5$

And the slope of line CD is equal to

$\left(\frac{1-3}{1-x}\right)$

$=\left(\frac{-2}{1-x}\right)$

Their product must be equal to -1

the slope of line AB×Slope of line CD = -1

$\Rightarrow-2.5 \times\left(\frac{-2}{1-x}\right)=-1 \Rightarrow 5=x-1$

⇒x = 6

 

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