Question:
$\frac{1}{(3+2 \sqrt{2})}=?$
(a) $\frac{3-2 \sqrt{2}}{17}$
(b) $\frac{(3-2 \sqrt{2})}{13}$
(c) $(3-2 \sqrt{2})$
(d) None of these
Solution:
$\frac{1}{(3+2 \sqrt{2})}=\frac{1}{(3+2 \sqrt{2})} \times \frac{(3-2 \sqrt{2})}{(3-2 \sqrt{2})}=\frac{(3-2 \sqrt{2})}{9-8}=(3-2 \sqrt{2})$
Hence, the correct answer is option (c).