Note Use $\pi=\frac{22}{7}$, unless stated otherwise.
A cloth having an area of $165 \mathrm{~m}^{2}$ is shaped into the form of a conical tent of radius $5 \mathrm{~m}$. (i) How many students can sit in the tent if a student, on an average, iccupies $\frac{5}{7} \mathrm{~m}^{2}$ on the ground? (ii) Find the volume of the cone.
Radius of the conical tent, r = 5 m
Area of the base of the conical tent $=\pi r^{2}=\frac{22}{7} \times 5^{2}=\frac{550}{7} \mathrm{~m}^{2}$
Average area occupied by a student on the ground $=\frac{5}{7} \mathrm{~m}^{2}$
∴ Number of students who can sit in the tent
$=\frac{\text { Area of the base of the conical tent }}{\text { Average area occupied by a student on the ground }}$
$=\frac{\frac{550}{7}}{\frac{5}{7}}$
$=110$
Thus, the number of students who can sit in the tent is 110.
Let the slant height of the tent be l m.
Curved surface area of the tent = 165 m2
$\therefore \pi r l=165$
$\Rightarrow \frac{22}{7} \times 5 \times l=165$
$\Rightarrow l=\frac{165 \times 7}{22 \times 5}$
$\Rightarrow l=10.5 \mathrm{~m}$
Let the height of the tent be h m.
$h=\sqrt{l^{2}-r^{2}}=\sqrt{(10.5)^{2}-5^{2}}=\sqrt{110.25-25}=\sqrt{85.25} \approx 9.23 \mathrm{~m}$
$\therefore$ Volume of the tent $=\frac{1}{3} \pi r^{2} h=\frac{1}{3} \times \frac{22}{7} \times(5)^{2} \times 9.23 \approx 241.74 \mathrm{~m}^{3}$
$\therefore$ Volume of the tent $=\frac{1}{3} \pi r^{2} h=\frac{1}{3} \times \frac{22}{7} \times(5)^{2} \times 9.23 \approx 241.74 \mathrm{~m}^{3}$