Solve the given inequalities $x+2 y \leq 100,2 x+y \leq 120, x+y \leq 70, x \geq 0, y \geq 0$ graphically in two dimensional plane.
The graphical representation of $x+2 y \leq 100,2 x+y \leq 120$
$x+y \leq 70, y \geq 0, x \geq 0$ is given by common region in the figure below.
$x+2 y \leq 100 \ldots \ldots$ (1)
$2 x+y \leq 120 \ldots \ldots$ (2)
$x \geq 0 \ldots \ldots$ (3)
$y \geq 0 \ldots \ldots$ (4)
$x+y \leq 70 \ldots \ldots$ (5)
Inequality (1) represents the region below line $x+2 y=100$ (including the line $x+2 y=100$ ).
Inequality (2) represents the region below line $2 x+y=120$ (including the line $2 x+y=120$ ).
Inequality (3) represents the region in front of line $x=0$ (including the line $x=0$ ).
Inequality (4) represents the region above line $y=0$ (including the line $y=0$ ).
Inequality (5) represents the region below line $x+y=70$ (including the line $x+y=70$ )
Therefore,every point in the common shaded region including the points on the respective lines represents the solution for the given inequalities.
This can be represented as follows,