Question:
Solve the following systems of equations:
$0.4 x+0.3 y=1.7$
$0.7 x-0.2 y=0.8$
Solution:
The given equations are:
$0.4 x+0.3 y=1.7 \ldots(i)$
$0.7 x-0.2 y=0.8 \ldots(i i)$
Multiply equation (i) by 2 and equation (ii) by 3 , and add both equations we get
Put the value of $x$ in equation $(i)$ we get
$0.4 \times 2+0.3 y=1.7$
$\Rightarrow 0.3 y=0.9$
$\Rightarrow y=3$
Hence the value of $x=2$ and $y=3$