Solve the following systems of equations:

The given equations are:

$23 x-29 y=98 \ldots(i)$

$29 x-23 y=110 \ldots($ ii $)$

Multiply equation $(i)$ by 23 and equation $(i i)$ by 29 and subtract (ii) from (i) we get

Put the value of $x$ in equation $(i)$, we get

$23 \times 3-29 y=98$

$\Rightarrow-29 y=29$

$\Rightarrow y=-1$

Hence the value of $x=3$ and $y=-1$