Solve the following systems of equations:

The given equations are:

$7(y+3)-2(x+2)=14$ $\ldots(i)$

$7 y-2 x=-3$

$4(y-2)+3(x-3)=2$  $\ldots(i i)$

$4 y+3 x=19$

Multiply equation $(i)$ by 3 and equation $(i i)$ by 2 and add both equations we get

Put the value of $x$ in equation $(i)$ we get

$7 \times 1-2 x=-3$

$\Rightarrow-2 x=-10$

$\Rightarrow x=5$

Hence the value of $x=5$ and $y=1$