Solve the following equation and verify your answer:

$\frac{2 y+5}{y+4}=1$

or $2 y+5=y+4$

or $2 y-y=4-5$

or $y=-1$

Thus, $y=-1$ is the solution of the given equation. Check :

Substituting $\mathrm{y}=-1$ in the given equation, we get:

L. H.S. $=\frac{2(-1)+5}{-1+4}=\frac{-2+5}{3}=\frac{3}{3}=1$

R.H.S. $=1$

$\therefore$ L. H.S. $=$ R. H.S. for $\mathrm{y}=-1$.