Solve the following equation and verify your answer:

$\frac{5 x-7}{3 x}=2$

or $6 \mathrm{x}=5 \mathrm{x}-7$ (After c ross multiplication)

or $6 \mathrm{x}-5 \mathrm{x}=-7$

or $\mathrm{x}=-7$

$\therefore \mathrm{x}=-7$ is the solution of given equation.

Check:

Substituting $x=-7$ in the given equation, we get:

L. H.S $=\frac{5 \times(-7)-7}{.3(-7)}=\frac{-35-7}{-21}=\frac{-42}{-21}=2$

R. H.S. $=2$

$\therefore$ L. H.S. $=$ R. H. S. for $x=-7$.