Solve the following equation and verify your answer:

$\frac{6}{2 \mathrm{x}-(3-4 \mathrm{x})}=\frac{2}{3}$

or $\frac{6}{6 \mathrm{x}-3}=\frac{2}{3}$

or $12 \mathrm{x}-6=18 \quad$ [After c ross multiplication]

or $12 \mathrm{x}=18+6$

or $\mathrm{x}=\frac{24}{12}$

or $\mathrm{x}=2$

Thus, $\mathrm{x}=2$ is the solution of the given equation. Check:

Substituting $x=2$ in the given equation, we get:

L.H.S. $=\frac{6}{2 \times 2-(3-4 \times 2)}=\frac{6}{9}=\frac{2}{3}$

R.H.S. $=\frac{2}{3}$

$\therefore$ L.H.S. $=$ R.H. S. for $\mathrm{x}=2$.