Solve the following equation and verify your answer:

$\frac{2-y}{y+7}=\frac{3}{5}$

or $10-5 y=3 y+21($ After c ross multipl ication $)$

or $3 y+5 y=10-21$

or $8 y=-11$

or $y=\frac{-11}{8}$

$\therefore y=\frac{-11}{8}$ is the solution of the given equation.

Check :

Substituting $\mathrm{y}=\frac{-11}{8}$ in the given equation, we get:

L. H.S. $=\frac{2-\frac{-11}{8}}{\frac{-11}{8}+7}=\frac{16+11}{-11+56}=\frac{27}{45}=\frac{3}{5}$

R.H.S. $=\frac{3}{5}$

$\therefore$ L. H.S. $=$ R.H.S. for $\mathrm{y}=\frac{-11}{8}$