Solve the following equation and verify your answer:

$\frac{2 x-3}{3 x+2}=-\frac{2}{3}$

or $6 \mathrm{x}-9=-6 \mathrm{x}-4$ (After c ross multipl ication)

or $6 x+6 x=-4+9$

or $\mathrm{x}=\frac{5}{12}$

$\therefore \mathrm{x}=\frac{5}{12}$ is the solution of the given equation.

Check:

L.H.S. $=\frac{2 \times \frac{5}{12}-3}{3 \times \frac{5}{12}+2}=\frac{\frac{5}{6}-3}{\frac{5}{4}+2}=\frac{\frac{-13}{6}}{\frac{13}{4}}=\frac{-4}{6}=\frac{-2}{3}$

R.H. S. $=\frac{-2}{3}$

$\therefore \mathrm{L} . \mathrm{H} . \mathrm{S} .=\mathrm{R} . \mathrm{H} . \mathrm{S} .$ for $\mathrm{x}=\frac{5}{12}$