Solve the following equation and verify your answer:

$\frac{2}{3 x}-\frac{3}{2 x}=\frac{1}{12}$

or, $\frac{4-9}{6 x}=\frac{1}{12}$

or, $\frac{-5}{x}=\frac{1}{2}$

or, $\mathrm{x}=-10[$ After $c$ ross multiplication $]$

Thus, $x=-10$ is the solution of the given equation.

Check :

Substituting $\mathrm{x}=-10$ in the given equation, we get:

L.H.S. $=\frac{2}{3(-10)}-\frac{3}{2(-10)}=\frac{2}{-30}-\frac{3}{-20}=\frac{4-9}{-60}=\frac{-5}{-60}=\frac{1}{12}$

R.H.S. $=\frac{1}{12}$

$\therefore \mathrm{L} . \mathrm{H} . \mathrm{S} .=\mathrm{R} . \mathrm{H} . \mathrm{S} .$ for $\mathrm{x}=-10$.