Solve the following equation and verify your answer:

$\frac{2 x}{3 x+1}=-3$

or $2 \mathrm{x}=-9 \mathrm{x}-3$       [ After c ross multipl ication ]

or $2 \mathrm{x}+9 \mathrm{x}=-3$

or $11 \mathrm{x}=-3$

or $\mathrm{x}=\frac{-3}{11}$

Thus, $\mathrm{x}=\frac{-3}{11}$ is the solution of the given equation. Check :

Substituting $\mathrm{x}=\frac{-3}{11}$ in the given equation, we get:

L.H.S. $=\frac{2\left(\frac{-3}{11}\right)}{3\left(\frac{-3}{11}\right)+1}=\frac{-6}{-9+11}=\frac{-6}{2}=-3$

R. H. S. $=-3$

$\therefore$ L.H.S. $=$ R.H. S. for $\mathrm{x}=\frac{-3}{11}$