Question: If $A=\left(\begin{array}{ll}2 & 2 \\ 9 & 4\end{array}\right)$ and $I=\left(\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right)$, then $10 A^{-1}$ is equal to
$4 \mathrm{I}-\mathrm{A}$
$\mathrm{A}-6 \mathrm{I}$
$6 \mathrm{I}-\mathrm{A}$
$\mathrm{A}-4 \mathrm{I}$
Correct Option: , 2
Solution:
