Solve the following

$\frac{6 y-5}{2 y}=\frac{7}{9}$

$\Rightarrow 9(6 y-5)=7(2 y) \quad$ (by cross multiplication)

$\Rightarrow 54 y-45=14 y$

$\Rightarrow 54 y-14 y=45$

$\Rightarrow 40 y=45$

$\Rightarrow y=\frac{45}{40}=\frac{9}{8}$

$\therefore y=\frac{9}{8}$