Solve the following

$\frac{8 x-3}{3 x}=2$

$\Rightarrow 8 x-3=2(3 x) \quad($ by cross multiplication $)$

$\Rightarrow 8 x-3=6 x$

$\Rightarrow 8 x-6 x=3$

$\Rightarrow 2 x=3$

$\Rightarrow x=\frac{3}{2}$

$\therefore x=\frac{3}{2}$