Solve the following

$\frac{3}{x-2}<1$

$\Rightarrow \frac{3}{x-2}-1<0$

$\Rightarrow \frac{3-x+2}{x-2}<0$

$\Rightarrow \frac{-x+5}{x-2}<0$

$\Rightarrow \frac{x-5}{x-2}>0$

$\therefore x \in(-\infty, 2) \cup(5, \infty)$