In a $\triangle P Q R$, if $3 \sin P+4 \cos Q=6$ and $4 \sin Q+3 \cos P=1$, then the angle $R$ is equal to :
$\frac{3 \pi}{4}$
$\frac{5 \pi}{6}$
$\frac{\pi}{6}$
$\frac{\pi}{4}$
Correct Option: , 3
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