Question:
$\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}+\mathrm{H}_{2} \mathrm{O} \stackrel{\text { Eerme } \mathrm{A}}{\longrightarrow} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$
Sucrose Glucose Fructose
$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \stackrel{\text { Engaae } \mathrm{B}}{\longrightarrow} 2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+2 \mathrm{CO}_{2}$
Glucose In the above reactions, the enzyme $A$ and enzyme $\mathrm{B}$ respectively are :-
Correct Option: , 3
Solution:
$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ Zymase $\longrightarrow 2 \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}+2 \mathrm{CO}_{2}$