Question:
$\mathrm{Al}_{2} \mathrm{O}_{3}$ was leached with alkali to get $\mathrm{X}$. The solution of $\mathrm{X}$ on passing of gas $\mathrm{Y}$ , forms Z. X, Y and $Z$ respectively are :
Correct Option: 1
Solution:
(1) $\mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{NaOH} \longrightarrow \mathrm{Na}\left[\mathrm{Al}(\mathrm{OH})_{4}\right]$
(2) $\mathrm{Na}\left[\mathrm{Al}(\mathrm{OH})_{4}\right] \underset{\text { "Y" }}{\stackrel{\mathrm{CO}_{2}}{\longrightarrow}} \mathrm{Al}(\mathrm{OH})_{3}$ or $\mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{xH}_{2} \mathrm{O}$