Question:
Solve:
$\frac{7 y+4}{y+2}=\frac{-4}{3}$
Solution:
$\frac{7 y+4}{y+2}=\frac{-4}{3}$
$\Rightarrow 3(7 y+4)=-4(y+2)$ (by cross multiplication)
$\Rightarrow 21 y+12=-4 y-8$
$\Rightarrow 21 y+4 y=-8-12$
$\Rightarrow 25 y=-20$
$\Rightarrow y=\frac{-20}{25}=\frac{-4}{5}$
$\therefore y=\frac{-4}{5}$