Question:
A bullet going with speed $350 \mathrm{~m} / \mathrm{s}$ enters a concrete wall and penetrates a distance $5.0 \mathrm{~cm}$ before coming to rest. Find the deceleration.
Solution:
$\mathrm{u}=350 \mathrm{~m} / \mathrm{s} ; \mathrm{v}=0 ; \mathrm{s}=5 \times 10^{-2} \mathrm{~m}$
$v^{2}=2^{2}+2 a s$
$0^{2}=(350)^{2}+2(a)(0.05)$
$\mathrm{a}=-12.25 \times 10^{5} \mathrm{~m} / \mathrm{s}^{2}$
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