Question: Diborane $\left(\mathrm{B}_{2} \mathrm{H}_{6}\right)$ reacts independently with $\mathrm{O}_{2}$ and $\mathrm{H}_{2} \mathrm{O}$ to produce, respectively;
$\mathrm{B}_{2} \mathrm{O}_{3}$ and $\mathrm{H}_{3} \mathrm{BO}_{3}$
$\mathrm{B}_{2} \mathrm{O}_{3}$ and $\left[\mathrm{BH}_{4}\right]^{-}$
$\mathrm{H}_{3} \mathrm{BO}_{3}$ and $\mathrm{B}_{2} \mathrm{O}_{3}$
$\mathrm{HBO}_{2}$ and $\mathrm{H}_{3} \mathrm{BO}_{3}$
Correct Option: 1
Solution:
