Question:
A cylinder rolls on a horizontal plane surface. If the speed of the centre is $25 \mathrm{~m} / \mathrm{s}$, what is the speed of the highest point?
Solution:
For pure rolling
$v_{C}=R \omega$
Speed at highest point= $\mathrm{v}+\quad R \omega$
$=2 \mathrm{v}$
$=2(25)$
$=50 \mathrm{~m} / \mathrm{s}$