If $(10)^{9}+2(11)^{1}(10)^{8}+3(11)^{2}(10)^{7}+\ldots \ldots+10(11)^{9}=\mathrm{k}(10)^{9}$, then $\mathrm{k}$ is equal to :
$\frac{121}{10}$
$\frac{441}{100}$
100
110
Correct Option: , 3
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