Solve each of the following systems of equations by the method of cross-multiplication :

GIVEN:

$2 x-y=6$

$x-y=2$

To find: The solution of the systems of equation by the method of cross-multiplication:

Here we have the pair of simultaneous equation

$2 x-y-6=0$

$x-y-2=0$

By cross multiplication method we get

$y=\frac{-2}{-1}=2$

Hence we get the value of $x=4$ and $\mathrm{y}=2$