Solve each of the following equation and also verify your solution:

$9 \frac{1}{4}=\mathrm{y}-1 \frac{1}{3}$

or $\frac{37}{4}+\frac{4}{3}=\mathrm{y}$ or $\mathrm{y}=\frac{127}{12}$

$\therefore \mathrm{y}=\frac{127}{12}$ for the given equation.

Check:

L. H.S $=9 \frac{1}{4}$

R. H.S $=\frac{127}{12}-1 \frac{1}{3}=\frac{127}{12}-\frac{4}{3}$