Solve each of the following equation and also check your result in each case:

$\frac{9 x+7}{2}-\left(x-\frac{x-2}{7}\right)=36$

or $\frac{63 \mathrm{x}+49-14 \mathrm{x}+2 \mathrm{x}-4}{14}=36$

or $\frac{51 \mathrm{x}+45}{14}=36$

or $51 \mathrm{x}+45=504$

or $51 \mathrm{x}=504-45$

or $\mathrm{x}=\frac{459}{51}=9$

Thus, $x=9$ is the solution of the given equation. Check :

Substituting $\mathrm{x}=9$ in the given equation, we get:

L.H.S. $=\frac{9 \times 9+7}{2}-\left(9-\frac{9-2}{7}\right)=\frac{88}{2}-9+\frac{7}{7}=44-9+1=36$

R.H.S. $=36$

$\therefore \mathrm{L} . \mathrm{H} . \mathrm{S} .=\mathrm{R} . \mathrm{H} . \mathrm{S} .$ for $\mathrm{x}=9 .$