Solve each of the following equation and also check your result in each case:

$\frac{3}{4} x+4 x=\frac{7}{8}+6 x-6$

or $\frac{3}{4} \mathrm{x}-2 \mathrm{x}=\frac{7}{8}-6$

or $\frac{3 x-8 x}{4}=\frac{7-48}{8}$

or $\frac{-5 x}{4}=\frac{-41}{8}$

or $-40 \mathrm{x}=-164$

or $\mathrm{x}=\frac{-164}{-40}=\frac{41}{10}$

Check :

L.H.S. $=\frac{3}{4} \times \frac{41}{10}+4 \times \frac{41}{10}=\frac{123}{40}+\frac{164}{10}=\frac{123+656}{40}=\frac{779}{40}$

R. H.S. $=\frac{7}{8}+6 \times \frac{41}{10}-6=\frac{7}{8}+\frac{246}{10}-6=\frac{35+984-240}{40}=\frac{779}{40}$

$\therefore$ L.H.S. $=$ R.H.S. for $x=\frac{41}{10}$