Solve each of the following equation and also check your result in each case:

$\frac{a-8}{3}=\frac{a-3}{2}$

or $2 a-16=3 a-9$

or $3 a-2 a=-16+9$

or $a=-7$

Verification :

L. H. S. $=\frac{-7-8}{3}=\frac{-15}{3}=-5$

R. H.S. $=\frac{-7-3}{2}=\frac{-10}{2}=-5$

$\therefore$ L.H.S. $=$ R.H.S. for $a=-7$