Question:
Solve each of the following equation and also check your result in each case:
$\frac{5 x}{3}-\frac{(x-1)}{4}=\frac{(x-3)}{5}$
Solution:
$\frac{5 x}{3}-\frac{x-1}{4}=\frac{x-3}{5}$
or $\frac{20 x-3 x+3}{12}=\frac{x-3}{5}$
or $\frac{17 x+3}{12}=\frac{x-3}{5}$
or $85 x+15=12 x-36$
or $73 x=-51$
or $x=\frac{-51}{73}$
Check :
L. H.S. $=\frac{5 \times \frac{-51}{73}}{3}-\frac{\frac{-51}{73}-1}{4}=\frac{-255}{219}-\frac{-124}{292}=\frac{-54}{73}$
R.H.S. $=\frac{\frac{-51}{73}-3}{5}=\frac{-54}{73}$
$\therefore$ L.H.S. $=$ R.H.S. for $x=\frac{-51}{73}$