Question: Solve each of the following Cryptarithm:
Solution:
$\mathrm{A}+\mathrm{B}=9$ as the sum of two digits can never be 19
$2+\mathrm{A}=0, \mathrm{~A}$ must be 8
$\mathrm{A}+\mathrm{B}=9,8+\mathrm{B}=9, \mathrm{~B}=1$
So, $\mathrm{A}=8, \mathrm{~B}=1$
