Solve each of the following Cryptarithm:

Two possibilities of A are :

(i) If $\mathrm{B}+7 \leq 9, \mathrm{~A}=6$

But clearly, if $\mathrm{A}=6, \mathrm{~B}+7 \geq 9$; it is impossible

(ii) If $\mathrm{B}+7 \geq 9, \mathrm{~A}=5$ and $\mathrm{B}+7=5$

Clearly, $\mathrm{B}=8$

$\therefore \mathrm{A}=5, \mathrm{~B}=8$