sin 38° – cos 52° = ?

Question:

sin 38° – cos 52° = ?

(a) 0

(b) 1

(c) $\frac{\sqrt{3}}{2}$

(d) $\frac{2}{\sqrt{3}}$

 

Solution:

$\sin 38^{\circ}-\cos 52^{\circ}$

$=\sin \left(90^{\circ}-52^{\circ}\right)-\cos 52^{\circ}$

$=\cos 52^{\circ}-\cos 52^{\circ} \quad\left(\because \sin \left(90^{\circ}-\theta\right)=\cos \theta\right)$

$=0$

Hence, the correct option is (a).

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