Question:
$\frac{16 m^{3} y^{2}}{4 m^{2} y}$
Solution:
$\frac{16 m^{3} y^{2}}{4 m^{2} y}$
$=\frac{16 \times m \times m \times m \times y \times y}{4 \times m \times m \times y}$
$=4 m^{(3-2)} y^{(2-1)}$
$=4 m y$
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