Question:
Simplify:
$\frac{32 m^{2} n^{3} p^{2}}{4 m n p}$
Solution:
$\frac{32 m^{2} n^{3} p^{2}}{4 m n p}$
$=\frac{32 \times m \times m \times n \times n \times n \times p \times p}{4 \times m \times n \times p}$
$=8 m^{(2-1)} n^{(3-1)} p^{(2-1)}$
$=8 m n^{2} p$
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